The value of x and y which satisfy the linear equation 2x+3y=16
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Answered by
2
Given that,
2x+3y=16
If x be 2 then,
2×2+3y=16
→4+3y=16
→3y=16-4
→3y=12
→y=12/3
→y=4
Hence, when x=2 then y=4,
Therefore, value of x & y which satisfies the given equation are 2 & 4 respectively.
Hope it helps you...
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Answered by
0
Answer:
Let x = 2
2×2+3y = 16
4+3y = 16
3y = 16-4 = 12
y = 12/3 = 4
x = 2
y = 4
let y = 2
2x+3×2 = 16
2x+6 = 16
2x = 16-6 = 10
x = 10/2 = 5
x = 5
y = 2
A linear equation , in two variables has infinity many solutions.
I hope it will helpful.
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