Question

the value of 'x'and'y' which satisfy the liner equation 2x+3y=16 are
A) x=5, y=2. B) x=2, y=5

C) x=-5, y=-2. D) x=-5, y=2​

Answer 1

Answer:

Solution:

The values of ‘x’ and ‘y’ which satisfy the linear equation 2x + 3y = 16.

Since the options are not given we can do by assuming the values of 'x' or 'y'.

Assume x = 2

2x + 3y = 16

=> 2(2) + 3y = 16

=> 4 + 3y = 16

=> 3y = 12

=> y = 4

2(2) + 3(4) = 16

Hence, the equation satisfied whenx= 2 and y = 4.

Assume y = 2

2x + 3y = 16

=> 2x + 3(2) = 16

=> 2x + 6 = 16

=> 2x = 10

=> x = 5

2(5) + 3(2) = 16

Hence, the equation satisfied when x = 5 and y = 2.

Assume x = 0

2x + 3y = 16

=> 2(0) + 3y = 16

=> 0 + 3y = 16

=> y = 16/3

2(0) + 3(16/3) = 16

Hence, the equation satisfied when x = 0 and y = 16/3.

Assume y = 0

2x + 3y = 16

=> 2x + 3(0) = 16

=> 2x + 0 = 16

=> x = 16/2

=> x = 8

2(8) + 3(0) = 16

Hence, the equation satisfied when x = 8 and y = 0.

Assume x = 6

2x + 3y = 16

=> 2(6) + 3y = 16

=> 12 + 3y = 16

=> 3y = 16 - 12

=> y = 4/3

2(6) + 3(4/3) = 16

Hence, the equation satisfied when x = 6 and y = 4/3.

There exist infinite solutions which satisfy the linear equation 2x + 3y = 16.

Step-by-step explanation:

Answer 2

Put x=6 and y=0 in given equation.

2x−3y=2×6−3×0

=12-0

=12

Hence, the value of x and y that satisfy the equation are (6,0).