Question

the value of x for the equation x^2+9x+18=6-4x​

Answer 1

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Answer 2

your question....

x²+9x+18=6-4x

x²+9x+4x+18-6=0

x²+13x+12=0

x²+12x+x+12=0

x(x+12)+1(x+12)=0

(x+1)(x+12)=0

x= -1,-12

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