Question

the value of x for the expression
(7/9)^4-x(7/9)^3x=(9/7)^-5​

Answer 1

Answer:

x = 1/2 or 0.5

Step-by-step explanation:

(7/9)^4 - x * (7/9)^3x = (9/7)^ - 5`

=> (7/9)^ (4 - x + 3x) = (9/7)^ -5                            [ a^n * a^m = a^(n+m) ]

=> (7/9)^ (4 + 2x) = (9/7)^ -5

=> (7/9)^ (4 + 2x) = (7/9)^ -(-5)                              [ a^ -1 = 1/a ]

=> (7/9)^ (4 + 2x) = (7/9)^ 5                                  [ - * - = + ]

=> 4 + 2x = 5                                                        [ If bases are equal then the                                      

=> 2x = 5 - 4                                                         powers should also be equal]    

=> 2x = 1

=> x = 1/2 or 0.5

 

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ALVIKA

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Answer 2

Answer:

Answers is 3

i hope the answer. will help you