Math, asked by singh533747, 7 months ago

The value of x for the minimum value of √3 cos +sin is *


Answers

Answered by daivikdalwadi10
3

Answer:

The value of 3cosx+5sin(x−π/6)

=3cosx+5(sinxcos6π−cosxsin6π)

=3cosx+253sinx−21cosx

=25cosx+253sinx

As −a2+b2≤asinθ+bcosθ≤a2+b2

∴−25≤25cosx+253sinx≤25

⇒−25≤3cosx+5sin(x−π/6)≤

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