Question

The value of x for the minimum value of √3 cos +sin is

Answer 1

Step-by-step explanation:

$\sqrt{3} cosx + sinx \\ 2( \frac{ \sqrt{3} }{2} cosx + \frac{1}{2} sinx) \\ 2sin(x + \frac{\pi}{6} ) \\ \\ for \: minimum \: value \: \\ sin(x + \frac{\pi}{6} ) = - 1 \\ x + \frac{\pi}{6} = - \frac{\pi}{2} \\ x = - \frac{2\pi}{3} \\ \\ hope \: it \: will \: help \: you \:$