Question

The value of x for which (2x + 1), (5x – 7) and (6x –1) are in

a.P. Is

Answer 1

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Answer 2

Common difference cannot be changed. So differennce in ( 2x + 1 ) , ( 5x - 7 ) and ( 6x - 1 ) will be same.



Difference between ( 6x - 1 ) and ( 5x - 7 ) = 6x - 1 - ( 5x - 7 ) = 6x - 5x - 1 + 7 = x + 6


Difference between ( 5x - 7 ) and ( 2x + 1 ) = 5x - 7 - ( 2x + 1 ) = 5x - 2x - 7 - 1 = 3x - 8




As we know that they common difference will be same.



Difference between 6x - 1 and 5x - 7 = Difference between 5x - 7 and 2x + 1



x + 6 = 3x - 8

6 + 8 = 3x - x

14 = 2x

7 = x



Therefore, value of x satisfying the equation is 7

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