Question

The value of x for which 2x s (x+10) and (3x + 2) are the three consecutive terms of an AP, is (a) 6 (b) - 6 (c) 18 (d) - 18​

Answer 1

Answer:

x+10 - 2x = 3x +2 - (x+10)

2(x+10) = 3x +2 + 2x

2x +20 = 5x +2

5x +2 = 2x +20

5x - 2x = 20 - 2

3x = 18

x = 18/3 = 6 Ans