Question

the value of x for which 2x,(x+10)and (3x+2) are the three consecutive terms of an ap is

Answer 1

Answer:

$\huge\underline\mathfrak\red{Answer}$

$(x+10)-2x = (3x+2)-(x+10). => x+10-2x = 3x+2-x-10.$

Answer 2

For an AP,
b-a=c-b
(x+10)-2x=(3x+2)-(x+10)
-x+10=2x-8
18=3x
6=x

Therefore value of x=6

Hope it will help you!!