Math, asked by harrysmarty298, 2 months ago

The value of x for which 2x, (x + 10) and (3x + 2) are
the three consecutive terms of an A.P., is

Answers

Answered by vipashyana1
10

Answer:

x=3

Step-by-step explanation:

a1=2x, a2=x+10, a3=3x+2

a2-a1=a3-a2

(x+10)-2x=(3x+2)-(x+10)

x+10-2x=3x+2-x-10

x-2x-3x-2x=2-10-10

(-6x)=(-18)

6x=18

x=18/6

x=3

Therefore, the value of x is 3.

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