the value of x for which 3x (x+8) and (5x+2) are three consecutive terms of an AP is
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Step-by-step explanation:
x+2,2x,2x+3 are in A.P.
⇒(2x)−(x+2)=(2x+3)−(2x)
2x−x−2=2x+3−2x
x−2=3
∴x=5
The consecutive numbers are : 5+2,2(5),2(5)+3
⇒7,10,13
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