Question

The value of X for which P1/P3+P1/P5=X+P3/P5

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Answer 1

Step-by-step explanation:

$\huge \boxed{ \red{QUESTION}} \\ \frac{p1}{p3} + \frac{p1}{p5} = x + \frac{p3}{p5} \\ x = \frac{p1}{p3} + \frac{p1}{p5} - \frac{p3}{p5} \\ = \frac{p1p5 + p1p3 - {(p3)}^{2} }{p3 \times p5}$

Answer 2

X = (P1.P3 + P1.P5 - P3^2)/(P1×P5)

Given

• P1/P3+P1/P5=X+P3/P5

To find

• The value of X

Solution

we are provided with an equation containing X and are asked to find the value of x for which the equation would hold right.

the left hand term of the equation as provided,.

P1/P3+P1/P5

or, P1(1/P3 + 1/P5)

or, (P1(P3 + P5))/(P1×P5)

combining this way to the right hand term of the equation

(P1(P3 + P5))/(P1×P5) = X+P3/P5

or, X = (P1(P3 + P5))/(P1×P5) - P3/P5 [ bringing the term to the right part and leaving the X at the LHS]

or, X = (P1.P3 + P1.P5)/(P1×P5) - P3/P5 [ taking LCM of both the terms]

Or, X = (P1.P3 + P1.P5 - P3^2)/(P1×P5) [ simplifying the terms]

Therefore, the X would be

X = (P1.P3 + P1.P5 - P3^2)/(P1×P5)