Math, asked by modydhvani, 4 months ago

The value of x for which --(x-1)(x-3)(x+5)<0​

Answers

Answered by Raghav1112
0

there are two negative sign in front they both get cancelled

(x-1)(x-3)(x+5)<0

(x^2 - 3x-x+3)(x+5)<0

(x^2 - 4x+3)(x+5)<0

(x^3-4x^2 +3x+5x^2 - 20x+15)

(x^3-x^2 - 17x+15)<0

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