The value of x from which 2x, (x + 10) and (3 x + 2) are consecutive terms of an AP is
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Given 2x,x+10 and 3x+2 are in A.P.
Given 2x,x+10 and 3x+2 are in A.P. Then we'll have,
Given 2x,x+10 and 3x+2 are in A.P. Then we'll have,2(x+10)=2x+3x+2
Given 2x,x+10 and 3x+2 are in A.P. Then we'll have,2(x+10)=2x+3x+2or, 2x+20=5x+2
Given 2x,x+10 and 3x+2 are in A.P. Then we'll have,2(x+10)=2x+3x+2or, 2x+20=5x+2or, 3x=18
Given 2x,x+10 and 3x+2 are in A.P. Then we'll have,2(x+10)=2x+3x+2or, 2x+20=5x+2or, 3x=18or, x=6.
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