Question

The value of x from which 2x, (x + 10) and (3 x + 2) are consecutive terms of an AP i​

Answer 1

a2-a1= a3-a2

x+10-2x = 3x+2-(x+10)

-x+10= 3x+2-x-10

-x -2x = -8 -10

-3x = -18

x= 6

2x = 2×6=12

x+10=6+10=16

3x+2= 3×6+2= 20