Math, asked by kuljit1341mohali, 12 days ago

The value of ‘x’ if ∠ = 35 degree, ∠B= 60degree and ∠ = 20degree is:

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Answers

Answered by madhugoel8212
0

Answer:- x= 115°

Hope this answer helps you !

Answered by robinhood9
93

∵The sum of the measure of all angles of triangle is 180° .

In \:  ∆ABC, \\  \\  \therefore \:  \angle \: CAB \:  +  \angle \:  ABC  +  \angle \: BCA \:  = 180 \degree \\  \therefore \: 35 \degree \:  + 60 \degree +  \angle \: BCA = 180 \degree \\  \therefore \: 95 \degree +  \angle \: BCA \:  = 180 \degree \\  \therefore \angle \: BCA \:  = 180 \degree \:  - 95 \degree  \\  \therefore  \boxed {\: \angle \: BCA = 85 \degree}

In  \: ∆ABC \:  and  \: ∆CDE , \\  \\  \therefore \angle \: BCA +  \angle \: ECD \:  = 180 \degree \\  - ( Angles \:  in  \: linear  \: pair ) \\  \therefore \: 85 \degree +  \angle \: ECD \:  = 180 \degree \\  \therefore \angle \: ECD \:  = 180 \degree - 85 \degree \\  \therefore \boxed { \angle \: ECD \:  = 95 \degree}

Theorem : The measure of an exterior angle of a triangle is equal to the sum of its remote interior angles.

  \angle \: x \: is \: the \:  exterior  \: angle  \: of  \: ∆ CDE \\  \therefore \angle \: ECD +  \angle \: EDC \:  =  \angle \: x  \\  \therefore \: 95 \degree \:  + 20 \degree \:  =  \angle \: x  \\  \therefore  \boxed{\angle \: x \:  = 115 \degree}

Option (iii) 115° is Correct.

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