The value of 'x' if 5x - 3= 3x - 5 is 2.
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Solution
Let (x+3)=Adxd(x2−2x−5)+B
(x+3)=A(2x−2)+B
Equating the coefficients of x and constant term on both sides, we obtain
2A=2⇒A=21
& −2A+B=3⇒B=4
∴(x+3)=21(2x−2)+4
⇒∫x2−2x−5x+2dx=∫x2−2x−521(2x−2)+4dx
=21∫x2−2x−52x−2dx+4∫x2−2x−51dx
Let I1=∫x2−2x−52x
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