the value of x in 1+5+9+13+...+x =496 is
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bhai last step kuch samaj m nahi aaya elaborate kr
n=16 hai toh 16th term nikala hai bas
by mistake
n=16
Answered by
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a=1
d=4
Using s= n[2a + (n-1)d]/2
496= n [ 2 + (n-1) 4 ]/2
2 n^2 + 31n -32n - 496 = 0
(n-16)(2n+31)= 0
n can't be negative
hence n = 16
x = T16
= a + (n-1)d
= 1 + (16-1)4
= 1 + 60
= 61
d=4
Using s= n[2a + (n-1)d]/2
496= n [ 2 + (n-1) 4 ]/2
2 n^2 + 31n -32n - 496 = 0
(n-16)(2n+31)= 0
n can't be negative
hence n = 16
x = T16
= a + (n-1)d
= 1 + (16-1)4
= 1 + 60
= 61
well try
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