Question

The value of x in given equation
p²x²-q²=0 ​

Answer 1

Answer:

p²x²-q²=0

(px)^2 - (q)^2=0

(px+q) (px-q) = 0

(px+q) = 0. and (px-q) = 0

x = -q/p. and. x = q/p

hope it helps you