Question

the value of x in:
$\frac{x}{2} - \frac{1}{4} (x - \frac{1}{3}) = \frac{1}{6} (x + 1) + \frac{1}{12}$
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Answer 1

Answer: 2

Explanation:

$\frac{x}{2}-\frac{1}{4}(x-\frac{1}{3})=\frac{1}{6}(x+1)+\frac{1}{12}$

$\Rightarrow \frac{x}{2}-\frac{x}{4}+\frac{1}{12}=\frac{x}{6}+\frac{1}{6}+\frac{1}{12}$

$\Rightarrow \frac{x}{2}-\frac{x}{4}-\frac{x}{6}=\frac{1}{6}$

$\Rightarrow 3x-\frac{3x}{2}-x=1$

$\Rightarrow \frac{6x-3x-2x}{2}=\frac{x}{2}=1$

$\Rightarrow x=2$

Hope it helped