The value of x in the following reaction
MnO2 +8H* + xe → Mn+2 +4H,O is
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Answer:
3 e- + MnO4- + 4 H+ → MnO2 + 2 H2O
Explanation:
This is an oxidation-reduction (redox) reaction:
MnVII + 3 e- → MnIV (reduction)
MnO4- is an oxidizing agent.
Reactants:
e-
MnO4-
H+
Hope it helps :)
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