Math, asked by Achi0910, 7 months ago

The value of x in the given equation.
4x^2 + 159 = 2x + 465​

Answers

Answered by prajapatijigar656
0

Answer:

Given equation is 4x2−2x+8=0

We know value of discriminant D=b2−4ac

Here a=4,b=−2,c=8

Therefore, D=(−2)2−4(4)(8)

=4−128

=−124<0

Hence, roots are not real.

Step-by-step explanation:

mark me as brainlist please

Similar questions