The. value of x in the x-b-c/a +x-c-a /b. + x-a-c /c =3
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x-b-c/a -1 + x-c-a/b -1 + x-a-b/c -1 = 0
x-a-b-c/a + x-a-b-c/b + x-a-b-c/c = 0
(x-a-b-c)(1/a +1/b + 1/c) =0
x = a+b+c
x-a-b-c/a + x-a-b-c/b + x-a-b-c/c = 0
(x-a-b-c)(1/a +1/b + 1/c) =0
x = a+b+c
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Answer:
x-b-c/a -1 + x-c-a/b -1 + x-a-b/c -1 = 0
x-a-b-c/a + x-a-b-c/b + x-a-b-c/c = 0
(x-a-b-c)(1/a +1/b + 1/c) =0
x = a+b+c
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