Math, asked by wwwjaiPrakashvevocom, 1 year ago

The. value of x in the x-b-c/a +x-c-a /b. + x-a-c /c =3

Answers

Answered by saimanda39p62pdu
1
x-b-c/a -1 + x-c-a/b -1 + x-a-b/c -1 = 0

x-a-b-c/a + x-a-b-c/b + x-a-b-c/c = 0

(x-a-b-c)(1/a +1/b + 1/c) =0

x = a+b+c
Answered by 2602alpha
0

Answer:

x-b-c/a -1 + x-c-a/b -1 + x-a-b/c -1 = 0

x-a-b-c/a + x-a-b-c/b + x-a-b-c/c = 0

(x-a-b-c)(1/a +1/b + 1/c) =0

x = a+b+c

Similar questions