Math, asked by wasifkamranmf, 5 hours ago

the value of x in which satisfies in equation 6x^2-x-2=0are_and_​

Answers

Answered by mufiahmotors
2

Step-by-step explanation:

Answer

6x

2

−x−2=0

6x

2

−4x+3x−2=0

2x(3x−2)+(3x−2)1=0

(2x+1)(3x−2)=0

2x+1 = 0 or 3x-2 = 0

x = -1/2 , x=2/3.

Answered by devildark494
3

Answer:

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