Question

the value of X (log y- log z) * Y (log z - log x) * Z (log X - log y) is equal to
a-5
b-3
c-1
d-0​

Answer 1

Answer:

Let y−zlogx=z−xlogy=y−zlogz=k

Now, 

xlogx+ylogy+zlogz=k[x(y−z)+y(z−x)+z(y−z)]

⇒logxx+logyy+logzz=0

⇒logxxyyzz=0

⇒xxyyzz=1

Step-by-step explanation:

hoping it would work out!!