the value of x^o+y^2is
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following is my interpretation of the this problem .
Could you please tell me where i am wrong
Stmt 1: XY <0
Case 1: XY <0
(POSITIVE) (NEGATIve)
Case 2: XY < 0
(Negative) (Positive)
Both cases satisy to give X+Y = -4
Stmt 1 Sufficient .
STMT2: X > 2 AND Y < 2
From above statement X is always postive and Y may be negative (or) Positive.
case 1: |x+2| = |y+2|
(x+2) = (-y+2)
case 2: |x+2| = |Y+2|
(X+2) = (Y+2)
How can we get X+Y = -4 from here on
and also from your above solution, i am unable to figure out if x and y are not equal, how come there will be only one solution .
Ex : if x= 5 (5>2) and y = 1 (1<2)
x+y = 6 and there are many values for x+y .
Help is appreciated.
Thanks in advance.
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