Question

the value of x satisfying log 10 x square - 4 x + 104 is equals to 2​

Answer 1

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Answer 2

Answer:

x=2

Step-by-step explanation:

$log_{10}( {x ^{2} } - 4x + 104) = 2 \\ 10 {}^{2} = x {}^{2} - 4x + 104 \\x {}^{2} - 4x + 4 = 0 \\ (x) {}^{2} - 2(x)(2) + (2) {}^{2} = 0 \\ (x - 2) {}^{2} = 0 \\ x = 2$

therefore, x=2 is the answer

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