Question

the value of x satisfying log³²x=0.8?​

Answer 1

Step-by-step explanation:

Given :-

log³²x=0.8

To find :-

Find the value of x ?

Solution :-

Given that

log³²x=0.8

We know that

a^x = N => log N to the base a = x

=> x = (32)^0.8

=> x = (32)^(8/10)

=> x = (32)^(4/5)

=> x = (2×2×2×2×2)^(4/5)

=> x = (2⁵)^(4/5)

=> x = 2^(5×4/5)

Since (a^m)^n = a^(mn)

=> x = 2^(20/5)

=> x = 2^4

=> x = 2×2×2×2

=> x = 16

Therefore , x = 16

Answer:-

The value of x for the given problem is 16

Used formulae:-

→ a^x = N => log N to the base a = x

→ (a^m)^n = a^(mn)