Question

The value of x satisfying p+7=0, q-12 = 0 and x square + px + q = 0 are

Answer 1

Answer:

a/q p= -7, q= 12

${x}^{2} - 7x + 12 = 0$

${x}^{2} - 4x - 3x + 12 = 0$

$(x - 4)(x - 3) = 0$

$x = 3 \: or \: 4$