Question

The value of x satisfying theequation, x 2+ v2- v2+xis:

Answer 1

let X+1= 0
X=-1

keeping this value of X= -1 in eqn

x^²+v^²-v^²+X

(-1)^²+v^²-v^²-1 =0


cancelling them =0

so the Value of X= -1 is satisfying

hope it help you

Answer 2

Let assume,  

x+1= 0

x= -1 --> Y)

keep this value as x = -1 in equation Y)

x²+v²-v²+x

(-1)² + v² - v² -1 = 0  --> A)

after cancel out every term  Eq A) becomes Zero “0”

so that  Value of x = -1 is the best value.

Hence Proved