Question

the value of x such that (3/7)power 3 ×(3/7) power -8 = (3/7) power 2x + 3​

Answer 1

Answer:

Step-by-step explanation:

(3/7)power 3-8= (3/7)power2x+3

(3/7)power(-5)= (3/7)power2x+3

As base are same so they will be canceled.

-5=2x+3

-5-3=2x

-8=2x

-8/2=x

x= -4

Answer 2

Answer:

According to the question, we have

2352 = 2 to power x × 3 to power y × 7 to power z

Or

2352 = 2^x + 3^y + 7^z  .............. (1)

The prime factorization of  2352 gives us

2352 = 2 × 2 × 2 × 2 × 3 × 7 × 7

2353 = 2^4 + 3^1 + 7^2    ............. (2)

Comparing (1) and (2) , we have

2^x + 3^y + 7^z  = 2^4 + 3^1 + 7^2

So we have  

x = 4 , y = 1 , z = 2

so we have

x + y + z = 4 + 1 + 2

x + y + z = 7