Question

The value of x when 18^4x-3 = (54root2)^3x-4

Answer 1

Answer:

18^4X-3 = √54^3X-4

=> 3^8X-6 × 2^4X-3 = 3^9X-12 × 2^3X-4

=> 4X-3-(3X-4) = X+1

=> X=-1

(IN THE CASE OF 2)

=> 9X-12-(8X-6)= X-6=0

=> X=6 (IN CASE OF 3).

THANK YOU .