Question

The value of 'X', when 3^ x = √3\9 is:​

Answer 1

Answer:

${3}^{x} = \frac{ \sqrt{3} }{9}$

${3}^{x} = \frac{3^{ \frac{1}{2} } }{ {3}^{2} }$

${3}^{x} = {3}^{ \frac{1}{2} - 2 }$

${3}^{x} = {3}^{ \frac{ - 3}{2} }$

As Bases are same,

$x = \frac{ - 3}{2}$

So that's your answer