Question

The value of x which makes the following statements true is
(3 7/11 ×11/5 ) ÷(3/7×x) =4/3

Answer 1

$\tt{ \frac{ \small{3 \frac{7}{11}} \times \frac{11}{5} }{ \frac{3}{7} \times x }= \frac{4}{3} } \\ \\ = > \bf3(3 \frac{7}{11} \times \frac{11}{5} ) = 4( \frac{3}{7} \times x) \\ \\ \bf = > \: \: \: \: \: \frac{120}{11} \times \frac{33}{5} = \frac{12}{7} \times 12x \\ \\ \bf = > \: \: \: \: \: \: \: \: \: \: \: \: 24 \times 3 = \frac{144x}{7} \\ \\ \bf= > \: \: \: \: \: \: \: \: \: x = \frac{(24 \times 3) \times 7}{144} \\ \\ \bf = > \: \: \: \: \: \: \: \: \:x = \frac{42}{12} = \frac{7}{2} = \red{ 3.5}$

Answer 2

The value of x is $3\dfrac{2}{3}$.

Explanation:

The given equation:

$(3\dfrac{7}{11}\times\dfrac{11}{15})\div(\dfrac{3}{7}\times x)=\dfrac{4}{3}$

$\Rightarrow\ (\dfrac{11(3)+7}{11}\times\dfrac{11}{15})\div\dfrac{3x}{7}=\dfrac{4}{3}\\\\ \Rightarrow\ (\dfrac{40}{11}\times\dfrac{11}{15})\times\dfrac{7}{3x}=\dfrac{4}{3}$

[To divide by a fraction is same as to multiply the reciprocal of it.]

$\Rightarrow\ \dfrac{8}{3}\times\dfrac{7}{3x}=\dfrac{4}{3}\\\\\Righarrow\ \dfrac{56}{9x}=\dfrac{4}{3}\\\\\Rightarrow\ 56\times 3=4\times9x\\\\\Rightarrow\ x=\dfrac{56\times3}{4\times9}=\dfrac{14}{3}=3\dfrac{2}{3}$

Hence, the value of x is $3\dfrac{2}{3}$.

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What is the value of x^3+x-x^2 if value of X is (-1)​

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