The value of {(x+y)^2/3 (x-y)^3/2/root x+y × root (x-y)^3}6 is
Answers
Answered by
87
the answer is above hope it will help you
Attachments:
Answered by
20
Answer:
The answer is x+y
Step-by-step explanation:
{(x+y)^2/3 (x-y)^3/2 / √x+y × √(x-y)^3}^6
= {(x+y)^2/3 (x-y)^3/2 / (x+y)^1/2×(x-y)^3/2}^6
= (x+y)^2/3 (x-y)^3/2 (x+y)^-1/2 (x-y)^-3/2}^6
= {(x+y)^2/3-1/2 (x-y)^3/2-3/2}^6
={(x+y)^4-3/6 (x-y)^0}^6
={(x+y)^1/6 (1)}^6
={(x+y)^1/6}^6
=x+y
Similar questions