Question

the value of {(x+y) ⅔(x-y) ³/²) /√(x+y) ×√(x-y) ³}6​

Answer 1

Answer:

((x+y)32⋅(x−y)32(x+y)32⋅(x−y)32)6

=((x+y)3/2(x+y)1/2)6[Assuming, x≠y≠0.]

={(x+y)32−12}6 [By the laws of exponent.]

=(x+y)1×6

=(x+y)6.†