Math, asked by vijayanand22, 1 year ago

The value of x-y^x-y
when x = 2 and y = -2, is
(b) - 18
(c) 14
a) 18
d)-14

Answers

Answered by Anonymous
2

Answer:

I THINK OPTIONS ARE WRONG

Step-by-step explanation:

x -  {y}^{x}  - y \\  = 2 - ( - 2) ^{2}  - ( - 2) \\  = 2 - 4 + 2 \\  = 4 - 4 \\  = 0


vijayanand22: the question is 2-(-2)^2-(-2)
Anonymous: yeah i too wrote like that only
vijayanand22: u wrote that x - (y to the power of x ) -y
Anonymous: you gave question like that
vijayanand22: please recheck the question
Similar questions