Math, asked by vijayanand22, 9 months ago

The value of x-y^x-y
when x = 2 and y = -2, is
(b) - 18
(c) 14
a) 18
d)-14

Answers

Answered by Anonymous

Answer:

I THINK OPTIONS ARE WRONG

Step-by-step explanation:

$x - {y}^{x} - y \\ = 2 - ( - 2) ^{2} - ( - 2) \\ = 2 - 4 + 2 \\ = 4 - 4 \\ = 0$

vijayanand22: the question is 2-(-2)^2-(-2)

Anonymous: yeah i too wrote like that only

vijayanand22: u wrote that x - (y to the power of x ) -y

Anonymous: you gave question like that

vijayanand22: please recheck the question

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