Question

the value of x-y^x-y when x=2 ; y= 2 is​

Answer 1

Answer: 1

Step-by-step explanation:

Substituting the values

(2-2)^(2-2)

0^0

Any number raised to the power 0 is always equal to 1

Therefore...

0^0 = 1

Hope it helps

Answer 2

Answer:

Hope the other one helps u