Question

The value of(x-y)(x+y)+(y-z)(y+z)+(z-x)(z+x)​

Answer 1

Answer:

Step-by-step explanation:

x²-y²+y²-z²+z²-x²=0

Answer 2

Step-by-step explanation:

(x-y)(x+y)+(y-z)(y+z)+(z-x)(z+x)

x2-y2+y2-z2+z2-x2

=0

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