Question

The value of x²-2x+7 when x=1

Answer 1

Answer:

Let y=

x

2

+2x+7

x

2

+2x+1

(y−1)x

2

+2(y−1)x+(7y−1)=0

Given that xϵR

∴△=4(y−1)

2

−4(y−1)(7y−1)≥0

(y−1)(y−1−7y+1)≥0

y(y−1)≤0

∴yϵ[0,1]

But y



= (∵ co efficient of x

2



=0)

∴yϵ[0,1)

∴

x

2

+2x+7

x

2

+2x+1

ϵ[0,1)

Answer 2

Answer:

6

Step-by-step explanation:

put x=1 in the equation and you will get your answer...

(1)^2 -2×1 +7

1-2+7

7-1

7

hope it helps...