Question

The value of x2 + 2y2 + 3xy at
x = 1 and y = -1 is​

Answer 1

Step-by-step explanation:

for x=1

1×2+2y2+3×1×y=0

2+4y+3y=0

2+7y=0

7y=-2

y=-2/7

Answer 2

Answer:

$given \: \: x^{2}+ 2y ^{2} + 3xy$

x= 1 and y = -1

putting value of x and y in equation

$(1)^{2} + 2( - 1)^{2} + 3 \times 1 \times ( - 1) \\ \\ = 1 + 2 - 3 \\ \\ = 0$

Hope it helps ☺️