Question

the value of x2-5 at x-1 is​

Answer 1

Here,

$\tt \huge p(x) = {x}^{2} - 5$

$\huge \tt{}g(x) = x - 1 \\ \\ \bf= > x - 1 = 0 \\ \bf= > x \: \: = 1$

Now,

$\huge \rm{}p(1) = {(1)}^{2} - 5 \\ \\ \huge \sf = > 1 - 5 = \red{- 4}$