the value of x2 -5 at x= -1 is
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hey dear here is your answer hope it helps you
Step-by-step explanation:
SOLUTION
We have the equation x2 – (a – 3)x – a –2 = 0.
its roots are m and n.
So, we have sum of roots = (m+n) = (a–3)
product of roots, mn = (–a–2)
Now m2+n2 = (m+n)2 – 2mn = (a–3)2 + 2(a+2)
= a2 + 9 – 6a + 2a + 4
= a2 - 4a + 4 + 9
= (a – 2)2 + 9
Since (a – 2)2 is a perfect square,
so its minimum value will be 0, when a = 2.
In that case, the minimum value of m2 + n2 will be 9.
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