Question

The value of x²^x + x (x²) when x = 2 is:​

Answer 1

Answer:

If x^2+x=1. then x^2-x=?

or. x^2+x-1=0

or. x=[-1+/-√(1+4)]/2.1

or. x=(-1+/-√5)/2……………(1)

or. Squaring both sides.

x^2=( 1+5-/+2√5)/4= (6-/+2.√5)/4.

x^2=(3-/+√5)/2………………….(2)

On subtracting eqn.(1) from (2)

x^2-x=(3-/+√5)/2-(-1+/-√5)/2=(3-/+√5+1-/+√5)/2

x^2-x=(4-/+2.√5)/2

x^2-x = 2-/+√5.

x^2-x=2-√5 or 2+√5. Answer.

Answer 2

Answer:

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