The value of x³-y³, when x=2 and y= 2 is
Answers
Answered by
1
Answer:
Basically, just plug in the values.
So.
2^3 - 2^3
Lets solve the first exponent. 2^3 is basically... 2 x 2 x 2 = 8
Lets solve the second exponent -2^3 is basically . . . -2 x -2 x -2 = -8
Lets re-write the equation with the new values.
8 - 8
Solve.
8-8 = 0
Hope this helped! Good luck
Answered by
15
0 is the answer okay dearrr
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