Math, asked by Pradyumna418, 4 months ago

The value of x³-y³, when x=2 and y= 2 is

Answers

Answered by Cottonnn
1

Answer:

Basically, just plug in the values.

So.

2^3 - 2^3

Lets solve the first exponent. 2^3 is basically... 2 x 2 x 2 = 8

Lets solve the second exponent -2^3 is basically . . . -2 x -2 x -2 = -8

Lets re-write the equation with the new values.

8 - 8  

Solve.

8-8 = 0

Hope this helped! Good luck

Answered by daddatyagi999
15

0 is the answer okay dearrr

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