Math, asked by ashokvirulkar123, 7 months ago

the value of x6 and y6​

Answers

Answered by itzheatless
5

Step-by-step explanation:

The required factored form of the given expression is (x+y)(x-y)(x^2-xy+y^2)(x^2+xy+y^2).(x+y)(x−y)(x

2

−xy+y

2

)(x

2

+xy+y

2

).

Step-by-step explanation: We are given to factorize the following expression :

E=x^6-y^6~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)E=x

6

−y

6

(i)

We will be using the following factorization formulas :

\begin{gathered}(i)~a^2-b^2=(a+b)(a-b),\\\\(ii)~a^3-b^3=(a-b)(a^2+ab+b^2),\\\\(iii)~a^3+b^3=(a+b)(a^2-ab+b^2).\end{gathered}

(i) a

2

−b

2

=(a+b)(a−b),

(ii) a

3

−b

3

=(a−b)(a

2

+ab+b

2

),

(iii) a

3

+b

3

=(a+b)(a

2

−ab+b

2

).

The factorization of given expression (i) is as follows :

\begin{gathered}E\\\\=x^6-y^6\\\\=(x^3)^2-(y^3)^2\\\\=(x^3+y^3)(x^3-y^3)\\\\=(x+y)(x^2-xy+y^2)(x-y)(x^2+xy+y^2)\\\\=(x+y)(x-y)(x^2-xy+y^2)(x^2+xy+y^2).\end{gathered}

E

=x

6

−y

6

=(x

3

)

2

−(y

3

)

2

=(x

3

+y

3

)(x

3

−y

3

)

=(x+y)(x

2

−xy+y

2

)(x−y)(x

2

+xy+y

2

)

=(x+y)(x−y)(x

2

−xy+y

2

)(x

2

+xy+y

2

).

Thus, the required factored form of the given expression is (x+y)(x-y)(x^2-xy+y^2)(x^2+xy+y^2).(x+y)(x−y)(x

2

−xy+y

2

)(x

2

+xy+y

2

).

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