The value of y for which (2y - 3)/(3y+2) = (-2/3) is
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Answer:
2y-3/3y+2 =-2/3
by cross multiplication
3(2y-3) =-2(3y+2)
6y-9=-6y-4
6y+6y=9-4
12y=5
y=5/12
Answered by
1
Answer..
2y - 3 / 3y + 2 = -2/3
=> 3(2y - 3) = -2(3y +2)
=> 6y - 9 = - 6y - 4
=> 12y = -4 + 9
=> 12y = 5
=> y = 5/12 (ans)
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