Math, asked by rishikaranshur, 9 months ago

The value of y for which (2y - 3)/(3y+2) = (-2/3) is

Answers

Answered by Anonymous
0

Answer:

2y-3/3y+2 =-2/3

by cross multiplication

3(2y-3) =-2(3y+2)

6y-9=-6y-4

6y+6y=9-4

12y=5

y=5/12

Answered by DeTsumibito
1

Answer..

2y - 3 / 3y + 2 = -2/3

=> 3(2y - 3) = -2(3y +2)

=> 6y - 9 = - 6y - 4

=> 12y = -4 + 9

=> 12y = 5

=> y = 5/12 (ans)

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