Question

The value of y for which 2y , (y + 10) and (2y + 2) are three consecutive terms of an A.P.:

Answer 1

EXPLANATION.

Three consecutive term of an Ap

sequence are = 2y , ( y + 10 ) , ( 2y + 2 )

As we know that,

Common difference = b - a = c - b

METHOD = 1.

=> ( y + 10 ) - ( 2y ) = ( 2y + 2 ) - ( y + 10 )

=> y + 10 - 2y = 2y + 2 - y - 10

=> 10 - y = y - 8

=> 10 + 8 = 2y

=> 18 = 2y

=> y = 9

METHOD = 2.

Conditions of an Ap

=> 2b = a + c

=> 2 ( y + 10 ) = 2y + 2y + 2

=> 2y + 20 = 4y + 2

=> 18 = 2y

=> y = 9

Therefore,

The value of y = 9.

Answer 2

y = 9

• Step-by-step explanation:

To Find :

• we have to find the Value of y.

Solution :

• AP :- 2y , (y + 10) , (2y + 2)

Common difference = a2 - a1 = a3 - a2

• a1 = 2y
• a2 = y + 10
• a3 = 2y + 2

≫ a2 - a1 = a3 - a2

≫ (y + 10) - 2y = (2y + 2) - (y + 10)

≫ - 2y + y + 10 = 2y - y - 10 + 2

≫ - y + 10 = y - 8

≫ 10 + 8 = y + y

≫ 18 = 2y

≫ y = 18/2

≫ y = 9

$\large\dag \large { \red{\underline{\bf{Hence }}}}$

• $\purple{\textrm{Value of y is 9}}$

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