Question

The value of y for which 2y, (y+10) and (3y+2) are three consecutive terms of an AP is

Answer 1

Answer:

y=6

Step-by-step explanation:

a=2y

b= (y+10)

c= (3y+2)

For three consecutive no.s in AP

b=(a+c)/2

y+10=(2y+3y+2)/2

2y+20=5y+2

18=3y

6=y

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