The value of y for which the distance between the points P(2, -3) and Q(10, y) is
(a) 9, 3
(b) 9, -3
(c)-9, 3
(d) -9, -3
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Answer:
Correct option is
B
-9, 3
PQ=10
⇒
(10−2)
2
+(y+3)
2
=10
64+y
2
+9+6y
=10
Squaring both sides,
y
2
+6y−27=0
⇒y
2
+9y−3y−37=0
⇒y(y+9)−3(y+9)=0
⇒(y+9)(y−3)=0
∴y=−9,3
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